/* keep iteration until the order is increasing from the last element. * When we finish the iteration, i will be at the index where i+1 was the last element * following the ascending order from the ...

java.util.ArrayList result = java_programs.NEXT_PERMUTATION.next_permutation(new java.util.ArrayList(java.util.Arrays.asList(3,2,4,1))); String resultFormatted = java ...